Thank you, I'll try as soon as possible!
Il 13/Feb/2015 22:28 "JS Huang [via R]" <
ml-node+s789695n470323...@n4.nabble.com> ha scritto:

> Or if you want to perform the calculation without using sd:
>
> sqrt((sum(p[,1]^2*p[,2])-(sum(p[,1]*p[,2]))^2/sum(p[,2]))/(sum(p[,2])-1))
>
>
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