Or, you can also do the same job using 'colSums()' as shown in the below:

> colSums(status=="I")
2010 2011 2012
   3    4    4
>

I hope this helps.

Chel Hee Lee

On 1/28/2015 7:31 PM, JSHuang wrote:
Hi,

   I think you need quotation around I like the following:
status
    2010 2011 2012
1     A    A    A
2     A    I    I
3     A    A    A
4     U    U    U
5     A    A    A
6     I    I    I
7     U    I    I
8     A    U    A
9     I    A    U
10    I    I    I
apply(start,2,function(x) {sum(x=="I",na.rm=TRUE)})
X2010 X2011 X2012
     3     4     4



--
View this message in context: 
http://r.789695.n4.nabble.com/problem-with-conditional-column-sums-tp4702426p4702434.html
Sent from the R help mailing list archive at Nabble.com.

______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to