Hi Monnand,
Is this what you are looking for?
data[grep("prefix1",data$name),]
data[grep("prefix2",data$name),]
Jim
On Wed, Jan 28, 2015 at 6:51 PM, Monnand <monn...@gmail.com> wrote:
> Hi all,
>
> This really annoyed since I thought this would be easy with some higher
> order function.
>
> Here is what I want:
>
> I have a data frame with two columns, one is ID, another one is Name. I
> want to get all rows whose name starts with some specific prefix. I thought
> this should be a one-liner instead of a long loop.
>
> My code (in an R console) is shown below, I thought we could use some
> boolean function to filter a data frame, but it seems I was wrong.
>
>> id = c(1,2)
>> name = c("prefix1.suffix1", "prefix2.suffix2")
>> data = data.frame(id, name)
>> # Next, define a function which chooses a specific prefix:
>> filtername = function(d) { unlist(strsplit(as.character(d$name),
> "[.]"))[[1]] == "prefix2" }
>> # This function seems work!
>> filtername(data[1,])
> [1] FALSE
>> filtername(data[2,])
> [1] TRUE
>> # Wrong results.
>> data[filtername(data),]
> [1] id name
> <0 rows> (or 0-length row.names)
>
> I would be appreciate if anyone could help.
>
> Thank you!
>
> -Monnand
>
> [[alternative HTML version deleted]]
>
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