On 02/12/2014 12:28, Pierrick Bruneau wrote:
I'll try to be more specific:
- ?order points to a common man page for both order() and sort.list()
- sort.list() has a "method" argument, i.e. a sorting algorithm. As far as
I can read, I'll rather say the default is "shell"
Not quite: the page says
method: the method to be used: partial matches are allowed. The
default is ‘"shell"’ except for some special cases: see
‘Details’.
- order() seems not to support this argument. My questions were thus 1)
what is the algorithm it uses ("shell" or other), and 2) is there a way to
parametrize it.
You are expected to read the source code to answer questions like that.
As order() is much more general than sort.list(), it needs much more
general sorting code.
But the overall message is
- when order() is doing the same job as sort.list it uses the same
defaults (which means it sometimes uses radix sorting).
- otherwise it uses a method from the Shell sort family.
On Tue, Dec 2, 2014 at 1:17 PM, PIKAL Petr <petr.pi...@precheza.cz> wrote:
Hi
Can you be more specific? How do you want parametrize order?
There is no sort.list argument in order.
For sort list, the default method is "radix", AFAIK.
Cheers
Petr
-----Original Message-----
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of
Pierrick Bruneau
Sent: Tuesday, December 02, 2014 12:33 PM
To: r-h...@stat.math.ethz.ch
Subject: [R] Sorting method used by order()
Hi all,
In ?order, the sorting method used appears as the "method" argument to
sort.list(), but I cannot make out which is used by default when
calling order(), and how to parametrize it.
Does someone have a clue there?
Thanks by advance,
Pierrick
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