I think the OP is being vague by saying "time format" (wouldn't a small 
reproducible example from the OP help right now)... if that is really another 
character string laid out as described then you might have difficulty with time 
zones for some values by converting to POSIXct first. If so, you can avoid the 
double conversion by using sub:

timestr <- "2014-08-13 00:30:00"
result <- sub("^(\\d{4})-(\\d{2})-(\\d{2}) (\\d{2}):(\\d{2}):(\\d{2})$", 
"\\1\\2\\3\\4\\5\\6", timestr )

---------------------------------------------------------------------------
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DCN:<jdnew...@dcn.davis.ca.us>        Basics: ##.#.       ##.#.  Live Go...
                                      Live:   OO#.. Dead: OO#..  Playing
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Sent from my phone. Please excuse my brevity.

On November 3, 2014 9:01:55 PM EST, Peter Alspach 
<peter.alsp...@plantandfood.co.nz> wrote:
>Tena koe
>
>For example:
>
>myTime <- Sys.time()
>myTime
>[1] "2014-11-04 14:58:10 NZDT"
>format(myTime, '%Y%m%d:%H%M%S')
>[1] "20141104:145810"
>
>My information in ?strptime.
>
>HTH ....
>
>Peter Alspach
>
>-----Original Message-----
>From: r-help-boun...@r-project.org
>[mailto:r-help-boun...@r-project.org] On Behalf Of TJUN KIAT TEO
>Sent: Tuesday, 4 November 2014 11:10 a.m.
>To: r-help@r-project.org
>Subject: [R] Convert time format to character
>
>Suppose I have a object in time format
>
>2014-08-13 00:30:00
>
>I want to convert it to a character string 20140813003000
>
>Is is possible ?
>
>Tjun Kiat
>                                         
>       [[alternative HTML version deleted]]
>
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