Ok, what i want is find how many numbers after . in a numeric ,and i don't
know if there is already exists a function to do it( i wrote one by myself
which will be showed later).
e.g.
1.234 has 3 numbers after .
1 has 0 number
1.5342 has 4 numbers
And i solved the above format using:
find<-function(x)
{
str<-as.character(x)
if(is.na(strsplit(str,"\\.")[[1]][2])) return(0)
else return(nchar(strsplit(str,"\\.")[[1]][2]))
}
But when i find(1.340) i get 2 not 3. find(1.3400) will also get 2 not 4.
So,my question is how to implement the above needing? TKS.
--
PO SU
mail: desolato...@163.com
Majored in Statistics from SJTU
At 2014-10-24 12:04:18, "Jeff Newmiller" <jdnew...@dcn.davis.ca.us> wrote:
>I am baffled. I think those were English words but they didn't make any sense
>to me. Not was there a reproducible example to turn to. Can you try again?
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>On October 23, 2014 8:35:06 PM PDT, PO SU <rhelpmaill...@163.com> wrote:
>>
>>Dear usRers,
>> Now i want to cal ,e.g.
>> cal(1.234) will get 3
>> cal(1) will get 0
>> cal(1.3045) will get 4
>> But the difficult part is cal(1.3450) will get 4 not 3.
>>So, is there anyone happen to know the solution to this problem, or it
>>can't be solved in R, because 1.340 will always be transformed autolly
>>to 1.34?
>>
>>
>>
>>
>>
>>
>>--
>>
>>PO SU
>>mail: desolato...@163.com
>>Majored in Statistics from SJTU
>>______________________________________________
>>R-help@r-project.org mailing list
>>https://stat.ethz.ch/mailman/listinfo/r-help
>>PLEASE do read the posting guide
>>http://www.R-project.org/posting-guide.html
>>and provide commented, minimal, self-contained, reproducible code.
>
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