Dear All,
Thanks for the useful ideas.
This is how I solved the problem and it works well.
####################################################################################
sowdays=function(data,Year){
Year = unique(data$Year)
#gives you sum of rain in 2 consecutive days
twodays <- rowSums(embed(Samaru56$Rain,2))
# the condition of heavy rainfall
sel <- which(twodays>=20)
#gives you vector of row numbers in which above condition results is TRUE
value
#Samaru56[sel,]
D=Samaru56[sel,]
day<- c()
for (year in 1928: 1983){
S <- subset(D, D$Year == year) #subset each year
for(i in S$Day[S$Day>91]){
if(S[S$Day == i, 3] >= 20){
day[year-(min(Year)-1)] = i
break
}
}
}
day
}
sowdays(Samaru56, Samaru56$Year)
#######################################################################################
I want to make it with the additional condition that there is no 10 day (or
longer) dry
spell in the next 30 days. In definition a 'dry day' is here defined as a
day with less than 0.85 mm of rain.
Any idea of how I can include this condition in the above condition is can
help me alot. Thanks.
Regards,
Fredo.
On Wed, Oct 15, 2014 at 6:34 PM, Jeff Newmiller <jdnew...@dcn.davis.ca.us>
wrote:
> twodays <- c(filter(x,c(1,1),sides=1))
>
> might be more efficient with memory than the embed approach, which might
> be important if more than two days were of interest.
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>
> On October 15, 2014 2:59:40 AM PDT, PIKAL Petr <petr.pi...@precheza.cz>
> wrote:
> >Hi
> >
> >twodays <- rowSums(embed(Samaru56$Rain,2))
> >
> >gives you sum of rain in 2 cosecutive days
> >
> >sel <- which(twodays>20)
> >
> >gives you vector of row numbers in which above condition results in
> >TRUE value
> >
> >Samaru56[sel,]
> >
> >selects these rows
> >
> >Regards
> >Petr
> >
> >> -----Original Message-----
> >> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> >> project.org] On Behalf Of Frederic Ntirenganya
> >> Sent: Wednesday, October 15, 2014 9:01 AM
> >> To: r-help@r-project.org
> >> Subject: [R] Sum of two consecutive number in dataset.
> >>
> >> Dear All,
> >>
> >> i am solving the following problem in my work.
> >>
> >> The first day from April 01 that gets more than 20 mm on a single
> >day,
> >> or totalled over 2 consecutive days. i.e April 01 = 92th day of the
> >> year.
> >>
> >> The column of interest is "Rain".
> >> > head(Samaru56)
> >> Year Day Rain
> >> 1 1928 1 0
> >> 2 1928 2 0
> >> 3 1928 3 0
> >> 4 1928 4 0
> >> 5 1928 5 0
> >> 6 1928 6 0
> >>
> >> I used the loop below but it is not printing anything.
> >>
> >> sow_day=c()
> >> for (i in 1928:1983){
> >> for (j in 92:366){
> >> k=j-1
> >> s_rain=Samaru56$Rain[k] + Samaru56$Rain[j]
> >> if (s_rain>=20)
> >> sow_day=j
> >> break
> >> }
> >> Samaru56$year=Samaru56$Year[sow_day]
> >> Samaru56$Day=Samaru56$Day[sow_day]
> >> Samaru56$Rain=Samaru56$Rain[sow_day]
> >> }
> >> sow_day
> >>
> >> Any idea is welcome on how I can solve this problem. Thanks
> >>
> >> --
> >> Frederic Ntirenganya
> >> Maseno University,
> >> Kenya.
> >> Mobile:(+254)718492836
> >> Email: fr...@aims.ac.za
> >> https://sites.google.com/a/aims.ac.za/fredo/
> >>
> >> [[alternative HTML version deleted]]
> >>
> >> ______________________________________________
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> >> PLEASE do read the posting guide http://www.R-project.org/posting-
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--
Frederic Ntirenganya
Maseno University,
Kenya.
Mobile:(+254)718492836
Email: fr...@aims.ac.za
https://sites.google.com/a/aims.ac.za/fredo/
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