Hi Duncan,
No, that's correct. Actually, I have data set below;
N= 1223
alpha= 0.05
Then
probability= 0.05/1223=0.0000408831
degree of freedom= 1223-2= 1221
So, TINV(0.0000408831,1221) returns 4.0891672
Could you show me more detail a manual equation. I really appreciate it if
you may give more detail.
Cheers!
On Wed, Oct 1, 2014 at 1:01 AM, Duncan Murdoch <murdoch.dun...@gmail.com>
wrote:
> On 30/09/2014 1:31 PM, Andre wrote:
>
>> Dear Sir/Madam,
>>
>> I am trying to use calculation for two-tailed inverse of the student`s
>> t-distribution function presented by Excel functions like
>> =TINV(probability, deg_freedom).
>>
>> For instance: The Excel function =TINV(0.0000408831,1221) = returns
>> 4.0891672.
>>
>> Would you like to show me a manual calculation for this?
>>
>> Appreciate your helps in advance.
>>
>
> That number looks pretty far off the true value. Have you got a typo in
> your example?
>
> You can compute the answer to your question as abs(qt(0.0000408831/2,
> df=1221)), but you'll get 4.117.
>
> Duncan Murdoch
>
>
>
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
