On 8/30/2014 2:11 PM, Felipe Carrillo wrote:
  library(plyr)
b <- structure(list(SampleDate = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L), .Label = "5/8/1996", class = "factor"), TotalCount = c(1L,
2L, 1L, 1L, 4L, 3L, 1L, 10L, 3L), ForkLength = c(61L, 22L, NA,
NA, 72L, 34L, 100L, 23L, 25L), TotalSalvage = c(12L, 24L, 12L,
12L, 17L, 23L, 31L, 12L, 15L), Age = c(1L, 0L, NA, NA, 1L, 0L,
1L, 0L, 0L)), .Names = c("SampleDate", "TotalCount", "ForkLength",
"TotalSalvage", "Age"), class = "data.frame", row.names = c(NA,
-9L))
b
ddply(b,.(SampleDate,Age),summarise,salvage=sum(TotalSalvage),pct=TotalCount/sum(TotalCount))
Error: expecting result of length one, got : 4

I get a slightly different error:

Error: length(rows) == 1 is not TRUE

but the problem is the same. sum returns a single value, while the computation for pct returns a vector the same length as TotalCount (the number of rows in the specific piece of b). summarise is designed to take a data frame and reduce the number of rows in it by aggregating/summarizing (some of) the columns. Since your two computations give different numbers of resulting rows, it errors out. It seems you don't want to reduce the number of rows, so replace summarise with mutate. That function can handle the different length return vectors and recycles appropriately.

(The other difference between summarise and mutate is that mutate keeps the original columns while summarise drops all original columns and returns only the computed ones; this makes sense given that summarise expects to return fewer rows than in the original data.)

#Computing TotalCount inside ddply works but the pct seems wrong...
ddply(b,.(SampleDate,Age),summarise,salvage=sum(TotalSalvage),Count=sum(TotalCount),pct=Count/sum(Count))
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--
Brian S. Diggs, PhD
Senior Research Associate, Department of Surgery
Oregon Health & Science University

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