> What if I just want the seconds vector without the date, please? Is there
> a convenient way to create such a vector, please?
Why do you want such a thing? E.g., do you want it to print the time
of day without the date? Or are you trying to avoid numeric problems
when you do regressions with the seconds-since-1970 numbers around
1414918800? Or is there another problem you want solved?
Note that the number of seconds in a day depends on the day and the
time zone. In US/Pacific time I get:
> length(seq(from=as.POSIXct("2014-08-12
00:00:00"),to=as.POSIXct("2014-08-12 23:59:59"), by="secs"))
[1] 86400
> length(seq(from=as.POSIXct("2014-03-09
00:00:00"),to=as.POSIXct("2014-03-09 23:59:59"), by="secs"))
[1] 82800
> length(seq(from=as.POSIXct("2014-11-02
00:00:00"),to=as.POSIXct("2014-11-02 23:59:59"), by="secs"))
[1] 90000
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Aug 12, 2014 at 11:51 AM, Erin Hodgess <erinm.hodg...@gmail.com> wrote:
> Hello!
>
> If I would like to generate a sequence of seconds for a date, I would do
> the following:
>
> x <- seq(from=as.POSIXct(2014-08-12 00:00:00),to=as.POSIXct(2014-08-12
> 23:59:59),by="secs")
>
> What if I just want the seconds vector without the date, please? Is there
> a convenient way to create such a vector, please?
>
> thanks,
> Erin
>
>
> --
> Erin Hodgess
> Associate Professor
> Department of Mathematical and Statistics
> University of Houston - Downtown
> mailto: erinm.hodg...@gmail.com
>
> [[alternative HTML version deleted]]
>
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