Dear William, Following Jim Holtman's solution to your previous post, you can do something similar to
Bill <- 1:100 # test data Bill.p <- split(Bill, rep(1:10, each=10)) sapply(Bill.p, function(x) mean(x)/0.8) 1 2 3 4 5 6 7 8 9 10 6.875 19.375 31.875 44.375 56.875 69.375 81.875 94.375 106.875 119.375 HTH, Jorge On Tue, Jun 3, 2008 at 10:36 PM, William Pepe <[EMAIL PROTECTED]> wrote: > > This is just a slight modification of a question I asked earlier. Thanks to > all the responders. > > I have a data set(Bill) of with 1 variable (var1), with 100 obs that are in > ascending order. I want to sample every 10 observations and save them in 10 > different groups such as Group1 is obs 1-10 Group 2 is obs-11-20 .... > Subset data into the 10 groups, then calculate the mean/0.8 of var1 for each > of the 10 groups. > The mean/0.8 is the modification. Thanks. > _________________________________________________________________ > It's easy to add contacts from Facebook and other social sites through Wi > https://www.invite2messenger.net/im/?source=TXT_EML_WLH_LearnHow > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
