No! Do not do this.

First, the syntax is wrong. Second, this will fail in general due to
floating point arithmetic. Use inequality with sufficient fuzz
instead.

e.g.
time <- time[time$TimeDiff < 14478,]

Moral: Caveat Emptor. Free advice may be worth exactly that.

Cheers,
Bert

Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374

"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll




On Mon, Jul 14, 2014 at 9:43 PM, Hasan Diwan <hasan.di...@gmail.com> wrote:
> Marta,
> To remove a row from your data frame, use:
>
> value <- 14478.4
> time <- time[-time[$TimeDiff] == value,]
>
> I hope that helps... If not, do push back. -- H
>
>
> On 14 July 2014 09:17, Marta valdes lopez <martavalde...@gmail.com> wrote:
>
>> Hi!
>>
>> I did this test and I got this outlier that i would like to remove the
>> whole row in my database; anyone knows how i can remove it?
>>
>>  chisq.out.test(time$TimeDiff)
>>         chi-squared test for outlier
>> data:  time$TimeDiff
>> X-squared = 73260.07, p-value < 2.2e-16
>> alternative hypothesis: highest value 14478.4 is an outlier
>>
>> Thank you!!
>>
>>         [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
> --
> Sent from my mobile device
> Envoyé de mon portable
>
>         [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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