You could use
which( sapply(l, length) == 2 )
but that still uses a loop internally.
On Thu, Jul 3, 2014 at 1:35 PM, carol white <wht_...@yahoo.com> wrote:
> Hi,
> Is there any way to access an element of a list without looping over the list
> nor using unlist? Just to avoid parsing a very long list.
>
>
> For ex, how to find a vector of a length 2 in a list without using a loop?
>
> l = list (c(1), c(2,3), c(1,2,3))
> for (i in 1:length(l))
> if(length(l[[i]]==2){
> print (i)
> break
> }
>
> Thanks
>
> Carol
>
> [[alternative HTML version deleted]]
>
>
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--
Gregory (Greg) L. Snow Ph.D.
538...@gmail.com
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