foo[[1:3]] asks for the 3rd member of the second component of the list that is nested within the 1st component of the top level list. You have no nested sublists, so this is clearly nonsense. You need to re-read ?"[" or consult The Introduction to R or other online tutorial to understand the semantics of "[[" with a vector of indices as argument.
Cheers, Bert Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom." Clifford Stoll On Thu, Jun 26, 2014 at 7:49 PM, ce <zadi...@excite.com> wrote: > Dear all, > > I have a list of arrays : > > foo<-list(A = c(1,3), B =c(1, 2), C = c(3, 1)) > >> foo > $A > [1] 1 3 > > $B > [1] 1 2 > > $C > [1] 3 1 > > I want to use all foo$A , foo$B and foo$C in a test : > >> foo$A[1] == 1 > [1] TRUE >> foo[[1]][1] == 1 > [1] TRUE >> foo[[1:3]][1] == 1 > Error in foo[[1:3]] : recursive indexing failed at level 2 > > > Is there a regular expression I can use ? > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
