Rich, If your data frame is called df, try
row.names(df) <- df$sampdate Jean On Thu, Jun 19, 2014 at 5:07 PM, Rich Shepard <rshep...@appl-ecosys.com> wrote: > I recall reading how to do this somewhere, but I cannot find just where I > read it. I have compositional data frames of this format: > > sampdate filter gather graze predate shred > 1 2000-07-18 0.0550 0.5596 0.0734 0.2294 0.0826 > 2 2003-07-08 0.0734 0.6147 0.0183 0.2294 0.0642 > 3 2005-07-13 0.1161 0.5714 0.0357 0.1696 0.1071 > 4 2006-06-28 0.1000 0.4667 0.1500 0.1333 0.1500 > 5 2010-09-14 0.0778 0.6111 0.0444 0.1889 0.0778 > 6 2011-07-13 0.0879 0.5714 0.0659 0.2747 0.0000 > 7 2012-07-11 0.1042 0.5313 0.0625 0.2396 0.0625 > > and the sampdate column should be the row headings rather than the numeric > sequence seen above. What is the command to move the sampdates to row > headers? > > Rich > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/ > posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
