Not necessarily. Missing values may base the means on unequal numbers of observation:
x <- c(1,1,1,2,NA,2) dim(x) <- c(3,2) cM <- colMeans(x, na.rm = TRUE, dims = 1) mean(cM) mean(x, na.rm = TRUE) B. On 2014-05-21, at 3:38 PM, Frede Aakmann Tøgersen wrote: > Hhhhmmmmmmhhhm, but is that not the same as > > mean(as.matrix(x)) > > ????? > > Yours sincerely / Med venlig hilsen > > > Frede Aakmann Tøgersen > Specialist, M.Sc., Ph.D. > Plant Performance & Modeling > > Technology & Service Solutions > T +45 9730 5135 > M +45 2547 6050 > fr...@vestas.com > http://www.vestas.com > > Company reg. name: Vestas Wind Systems A/S > This e-mail is subject to our e-mail disclaimer statement. > Please refer to www.vestas.com/legal/notice > If you have received this e-mail in error please contact the sender. > > >> -----Original Message----- >> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] >> On Behalf Of Sarah Goslee >> Sent: 21. maj 2014 21:11 >> To: Kate Ignatius; r-help >> Subject: Re: [R] Mean of colMeans >> >> That would be because col is a function in base R, and thus a poor >> choice of names for user objects. Nonetheless, it worked when I ran >> it, but you didn't provide reproducible example so who knows. >> >> R> set.seed(1) >> R> x <- data.frame(matrix(runif(150), ncol=10)) >> R> # col is a function, so not a good name >> R> col <- colMeans(x) >> R> mean(col) >> [1] 0.5119 >> >> It's polite to include the list on your reply. >> >> Sarah >> >> On Wed, May 21, 2014 at 2:50 PM, Kate Ignatius <kate.ignat...@gmail.com> >> wrote: >>> That didn't work: gave me the error = >>> >>> [1] NA >>> Warning message: >>> In mean.default(col) : argument is not numeric or logical: returning NA >>> >>> But writing it like: mean(colMeans(x, na.rm = TRUE, dims = 1)), worked >>> >>> Thanks! >>> >>> On Wed, May 21, 2014 at 2:31 PM, Sarah Goslee >> <sarah.gos...@gmail.com> wrote: >>>> Is >>>> >>>> mean(col) >>>> >>>> not what you're looking for? >>>> >>>> Sarah >>>> >>>> On Wed, May 21, 2014 at 2:26 PM, Kate Ignatius >> <kate.ignat...@gmail.com> wrote: >>>>> Hi All, >>>>> >>>>> I've successfully gotten out the colMeans for 60 columns using: >>>>> >>>>> col <- colMeans(x, na.rm = TRUE, dims = 1) >>>>> >>>>> My next question is: is there a way of getting a mean of all the >>>>> column means (ie a mean of a mean)? >>>>> >>>>> Thanks! >>>>> >> >> -- >> Sarah Goslee >> http://www.functionaldiversity.org >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting- >> guide.html >> and provide commented, minimal, self-contained, reproducible code. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
