Hello,
Maybe you want
by(tr$srv_dt, tr$Rmbr, diff, lag=1, difference=1)
Can't you ?dput a data example?
dput(head(tr, 30)) # paste the output of this in a post
Hope this helps,
Rui Barradas
Em 10-03-2014 16:10, Mckinstry, Craig escreveu:
I have been trying to process a data.frame (tr) on a grouping factor (Rmbr)
using diff
to find differences between srv_dt (a date) by Rmbr and keep getting the
following error message
tmp <- by(tr,tr$Rmbr, diff, tr$srv_dt, lag=1, difference=1)
Error in r[i1] - r[-length(r):-(length(r) - lag + 1L)] :
non-numeric argument to binary operator
# the only two arguments I supply are both numeric
mode(tr$srv_dt)
[1] "numeric"
mode(tr$Rmbr)
[1] "numeric"
IMPORTANT NOTICE: This communication, including any attachment, contains
information that may be confidential or privileged, and is intended solely for
the entity or individual to whom it is addressed. If you are not the intended
recipient, you should delete this message and are hereby notified that any
disclosure, copying, or distribution of this message is strictly prohibited.
Nothing in this email, including any attachment, is intended to be a legally
binding signature.
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
