Arun et al.
Thanks,
This is exactly what I need.
All the best,
KW
--
On Mar 7, 2014, at 10:59 PM, arun <smartpink...@yahoo.com> wrote:
> Try:
> oof1 <- list()
> oof1[foo$name] <- foo$num
> A.K.
>
>
>
>
> On Friday, March 7, 2014 10:43 PM, Keith S Weintraub <kw1...@gmail.com> wrote:
> Folks,
>
> I have a data frame as follows:
>
>> foo<-structure(list(name = c("A", "B", "C"), num = c(3L, 2L, 1L)), .Names =
>> c("name",
> "num"), row.names = c(NA, -3L), class = "data.frame")
>
>> str(foo)
> 'data.frame': 3 obs. of 2 variables:
> $ name: chr "A" "B" "C"
> $ num : int 3 2 1
>
>> foo
> name num
> 1 A 3
> 2 B 2
> 3 C 1
>
> I want to convert this to a list like so:
>
>> oof<-list(A = 3, B = 2, C = 1)
>
>> str(oof)
> List of 3
> $ A: num 3
> $ B: num 2
> $ C: num 1
>
>> oof
> $A
> [1] 3
>
> $B
> [1] 2
>
> $C
> [1] 1
>
> Any Suggestions?
>
> Thanks,
> KW
>
> --
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
