Hi,

First, if you want a precise answer, provide a precise question. That is, provide a reproducible example. A good function for that is dput(), with which you can copy/paste your own data. If your data is too long, create a relevant subset (with head() for example).

Regarding your question: are you looking for table()?

HTH,
Ivan

--
Ivan Calandra, ATER
Université de Franche-Comté
UFR STGI - UMR 6249 Chrono-Environnement
4 Place Tharradin - BP 71427
25211 Montbéliard Cedex, FRANCE
ivan.calan...@univ-fcomte.fr
http://biogeosciences.u-bourgogne.fr/calandra

Le 02/03/14 18:26, KarlSmithByrne a écrit :
I have a large genotype dataset. Each person can take the value Hom or Het
(Homozygous or Heterozygous variant), for example.

There is also a column variable that tells me if each "Hom" is also damaging
or activating, for example.

I am trying to write a function that will tell me how many "Hom" and "Het"
are also Damaging or Activating, and that are shared across all individuals
- without much luck.

As I see it, for individuals 1 through 40 I want to extract values "Hom" and
"Het" that are also "Damaging" or "Activating", provided this is true for
all other individuals.

This may be an easy task and I am just not getting it.

Thank you for any help you give!



--
View this message in context: 
http://r.789695.n4.nabble.com/Difficulty-with-what-is-probably-a-basic-function-to-retrieve-data-from-a-data-frame-tp4686108.html
Sent from the R help mailing list archive at Nabble.com.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to