Also, rownames(which(t(!!A[,-1]),arr.ind=TRUE)) A.K.
On Thursday, February 20, 2014 6:48 PM, arun <smartpink...@yahoo.com> wrote: Hi, May be this helps: A$Variable <- rep(colnames(A[,-1]),nrow(A))[t(!!A[,-1])] A.K. On Thursday, February 20, 2014 5:55 PM, ioanna ioannou <ii54...@msn.com> wrote: Hello, Assuming that I have a data frame A<-data.frame(A=c(10,100,1000,30,50,60,300), B=c(0,1,1,1,0,0,0), C=c(0,0,0,0,1,1,0), D=c(1,0,0,0,0,0,1)) What I would like is to introduce a new column Variable such that: A<-data.frame(A=c(10,100,1000,30,50,60,300), B=c(0,1,1,1,0,0,0), C=c(0,0,0,0,1,1,0), D=c(1,0,0,0,0,0,1), Variable=c(D,B,B,B,C,C,D)) How can I do it? Best IOanna [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
