Hello Bart,
I solved your problem.
Please find the code given below,
****************************************************************************************************************************************
dat <-structure(list(Batch = c(1L, 1L, 2L, 2L, 3L, 3L, 4L, 4L, 4L, 4L,
4L, 4L), Test = structure(c(1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 2L,
2L), .Label = c("A", "B"), class = "factor"), Result = structure(c(12L,
4L, 8L, 6L, 11L, 5L, 10L, 2L, 9L, 3L, 1L, 7L), .Label = c("6,604 - 6,59
- 6,585 - 6,588", "6,61", "6,625 - 6,607", "6,675", "6,71 - 6,74", "6,76
- 6,75", "6,79 - 6,80", "98,28 - 99,14", "98,52", "99,05 - 99,15",
"99,74 - 98,19", "99,77 - 99,62"), class = "factor"), X = c(NA, NA, NA,
NA, NA, NA, NA, NA, NA, NA, NA, NA), LL = structure(c(2L, 1L, 2L, 1L,
2L, 1L, 2L, 1L, 2L, 1L, 1L, 1L), .Label = c("6.00", "95"), class =
"factor")), .Names = c("Batch","Test", "Result", "X", "LL"), class =
"data.frame", row.names = c(NA, -12L))
dat1<-NULL
rno<-0
for (thisResult in dat$Result)
{
rno<-rno+1
resTemp<-unlist(strsplit(thisResult," - "))
i<-length(resTemp)
if(i>1)
{
for(j in 1:i)
{
rbind(dat1,data.frame(Batch=paste(dat$Batch[rno]
,".",j),Test=dat$Test[rno],Result=resTemp[j],X=dat$X[rno],LL=dat$LL[rno]))->dat1
j=j+1
}
}
else
{
rbind(dat1,data.frame(Batch=toString(dat$Batch[rno]),Test=dat$Test[rno],Result=dat$Result[rno],X=dat$X[rno],LL=dat$LL[rno]))->dat1
}
}
dat1
rm(dat1,i,j,resTemp,thisResult,rno)
***************************************************************************************************************************************
Output :
Batch Test Result X LL
1 1 . 1 A 99,77 NA 95
2 1 . 2 A 99,62 NA 95
3 1 B 6,675 NA 6.00
4 2 . 1 A 98,28 NA 95
5 2 . 2 A 99,14 NA 95
6 2 . 1 B 6,76 NA 6.00
7 2 . 2 B 6,75 NA 6.00
8 3 . 1 A 99,74 NA 95
9 3 . 2 A 98,19 NA 95
10 3 . 1 B 6,71 NA 6.00
11 3 . 2 B 6,74 NA 6.00
12 4 . 1 A 99,05 NA 95
13 4 . 2 A 99,15 NA 95
14 4 B 6,61 NA 6.00
15 4 A 98,52 NA 95
16 4 . 1 B 6,625 NA 6.00
17 4 . 2 B 6,607 NA 6.00
18 4 . 1 B 6,604 NA 6.00
19 4 . 2 B 6,59 NA 6.00
20 4 . 3 B 6,585 NA 6.00
21 4 . 4 B 6,588 NA 6.00
22 4 . 1 B 6,79 NA 6.00
23 4 . 2 B 6,80 NA 6.00
Thanks & Regards,
*Mr. Jayesh B. Baviskar
Pune, India.
*On 2/20/2014 2:34 PM, Bart Joosen [via R] wrote:
> Hi,
>
> I have a dataframe with some data from experiments:
> Batch Test Result LL ......(many more columns, all
> the same within Batch/Test)
> 1 A 6,5-6,7 6,00 .....
> 1 B 95,1-95,3 95,00 .....
> 2 A 6,5-6,7 6,00 .....
> ...
>
> Some results have double values, instead of 1 single numeric value,
> all separated by "-".
> But now I want a dataframe with only 1 value per Batch/Test, and
> batches with double values should be renamed to 1a, 1b, ...
>
> So
> Batch Test Result LL ......(many more columns, all
> the same within Batch/Test)
> 1a A 6,5
> 1b A 6,7 6,00 .....
> 1a B 95,1 95,00 .....
> 1b B 95,3 95,00 .....
> 2a A 6,5 6,00 .....
> 2b A 6,7 6,00 .....
> ...
>
> I tried with by and strsplit, but couldn't figure it out.
> Any help would be appreciated, example data below.
>
> Bart
>
>
> dat <-
> structure(list(Batch = c(1L, 1L, 2L, 2L, 3L, 3L, 4L, 4L, 4L,
> 4L, 4L, 4L), Test = structure(c(1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L,
> 1L, 2L, 2L, 2L), .Label = c("A", "B"), class = "factor"), Result =
> structure(c(12L,
> 4L, 8L, 6L, 11L, 5L, 10L, 2L, 9L, 3L, 1L, 7L), .Label = c("6,604 -
> 6,59 - 6,585 - 6,588",
> "6,61", "6,625 - 6,607", "6,675", "6,71 - 6,74", "6,76 - 6,75",
> "6,79 - 6,80", "98,28 - 99,14", "98,52", "99,05 - 99,15", "99,74 -
> 98,19",
> "99,77 - 99,62"), class = "factor"), X = c(NA, NA, NA, NA, NA,
> NA, NA, NA, NA, NA, NA, NA), LL = structure(c(2L, 1L, 2L, 1L,
> 2L, 1L, 2L, 1L, 2L, 1L, 1L, 1L), .Label = c("6,00", "95"), class =
> "factor")), .Names = c("Batch",
> "Test", "Result", "X", "LL"), class = "data.frame", row.names = c(NA,
> -12L))
>
>
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