On 13/02/2014 15:51, Marc Schwartz wrote:
On Feb 13, 2014, at 8:43 AM, Rainer M Krug <rai...@krugs.de> wrote:
Hi
I want to search for multiple pattern as grep is doing for a single
pattern, but this obviously not work:
grep("an", month.name)
[1] 1
grep("em", month.name)
[1] 9 11 12
grep("eb", month.name)
[1] 2
grep(c("an", "em", "eb"), month.name)
[1] 1
Warning message:
In grep(c("an", "em", "eb"), month.name) :
argument 'pattern' has length > 1 and only the first element will be used
Is there an equivalent which returns the positions as grep is doing, but
not using the strict full-string matching of match()?
I could obviously do:
unlist( sapply(pat, grep, month.name ) )
an em1 em2 em3 eb
1 9 11 12 2
but is there a more compact command I am missing?
Thanks,
Rainer
The vertical bar '|' acts as a logical 'or' operator in regex expressions:
grep("an|em|eb", month.name)
[1] 1 2 9 11 12
grep("an|em|eb", month.name, value = TRUE)
[1] "January" "February" "September" "November" "December"
Regards,
Marc Schwartz
and if you want your patterns in a vector
> pat <-c("an", "em", "eb")
> grep(paste(pat, collapse="|"), month.name)
[1] 1 2 9 11 12
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