Hi,
> I wouldn't call it a bug, but it's a documented limitation, if you know
> how to read it. As documented, the expression is evaluated with the
> caller's environment as the parent environment. But here the caller is
> some code in lapply, not your function f. x is not found there.
Thanks! That explains it.
> I think this modification works, and is maybe the simplest way to get it
> to work:
>
> f <- function(x){
> y <- list(y1=list())
> mywithin <- function(...) within(...)
> y <- lapply(y, mywithin, {z<-x})
> y
> }
>
> The idea here is that the calling frame of f is the environment of
> mywithin(), so x is found there.
It works.
Best regards,
Pavel
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