On 27-11-2013, at 05:16, Binod Manandhar <gibi...@yahoo.com> wrote: > I was trying to find root for two non-linear equations. My equation is > similar as follows: > 120 – 5* exp(b0+b1*4) > / (1+ exp(b0+b1*4) ) = 0 > 690 – 31* > exp(b0+b1*4) / (1+ exp(b0+b1*4) ) =0 > > How could find value of bo and b1 root values? > Thank you in advance.
You can use packages nleqslv, BB, (and ktsolve) for solving systems of non linear equations. See the taskviews Optimization and NumericalMathematics on CRAN. But you will not succeed in your case. In your equations replace the expression exp(b0+b1*4) / (1+ exp(b0+b1*4) ) with Z. Then you have two linear equations: 120-5*Z=0 690-31*Z=0 The system is incompatible. You can’t solve this for Z. So you need to rethink your equations. Berend > > Saymi > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
