On 17-11-2013, at 15:47, Benjamin Gillespie <gy...@leeds.ac.uk> wrote:
> Hi all,
>
> I hope you can help.
>
> I have a data frame 'df':
>
> group=c(rep(1,8),rep(2,10),rep(3,11))
> var=rnorm(29)
> time=c(seq(1,8),seq(1,10),seq(1,11))
> df=data.frame(group,var,time)
>
> I would like to extract the value from 'var' for each 'group' at 'time'=4 and
> repeat these extracted values in a new vector ('new') n times where n is the
> number of rows for each group. I did this by hand as below, but there must be
> a quicker way:
>
> subset=subset(df,df$time==4)
> subset
> group var time
> 4 1 0.2531270 4
> 12 2 -0.3600128 4
> 22 3 0.4194730 4
>
> df$new=c(rep(0.2531270,8),rep(-0.3600128,10),rep(0.4194730,11))
>
> Any questions please ask,
A very similar question was recently asked on Stackoverflow:
http://stackoverflow.com/questions/19971763/r-programming-normalizing-a-column-of-data-by-another-entry-in-2-other-columns
>From the answer given there you could try this
set.seed(11) # to make it reproducible
group=c(rep(1,8),rep(2,10),rep(3,11))
var=rnorm(29)
time=c(seq(1,8),seq(1,10),seq(1,11))
df=data.frame(group,var,time)
#df
#df[df$time==4, c("group", "var")]
# merge into original data.frame
df <- merge(df, df[df$time == 4, c("group", "var")], by.x = "group", by.y =
"group", suffixes = c("", "GroupSK0"))
df
Berend
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