HI, You could try: library(lubridate) Date1 <- mdy(as.character(df[,1])) Date1[is.na(Date1)] <- parse_date_time(paste(1,as.character(df[,1][is.na(Date1)]),sep="-"),"%d-%b-%y")
A.K. On Tuesday, November 5, 2013 12:38 PM, Abraham Mathew <abmathe...@gmail.com> wrote: Let's say I have the following data frame and the date column has two different ways in which date is presented. How can I use as.Date or the lubridate package to have one date structure for the entire colum df = data.frame(Date=c("5/1/13","8/1/13","9/1/13","Apr-10", "Apr-11","Apr-12","Apr-13")) It's "month/date/year" and "month-year". An alternative approach would be to perform some conditional statements where if the date is "Apr-11", then populate it with "04/01/2011". [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.