I'm not honestly sure why data.matrix didn't work off hand. Perhaps
another user can shed some light on this. An alternative is the following:
apply(dat, 2, FUN = function(x) as.numeric(as.character(x)))
On Thu, Oct 10, 2013 at 8:26 AM, arun <smartpink...@yahoo.com> wrote:
> Did you mean to apply it like this or is it something else?
> data.matrix(dat) #
> a coef coef.l coef.h
> 1 1 3 4 2
> 2 2 4 5 4
> 3 3 1 1 1
> 4 4 2 2 3
> 5 5 5 3 5
>
>
> A.K.
>
>
>
>
>
>
> On Thursday, October 10, 2013 9:09 AM, Charles Determan Jr <
> deter...@umn.edu> wrote:
>
> data.matrix() should do the job for you
>
> Charles
>
>
>
>
> On Thu, Oct 10, 2013 at 8:02 AM, arun <smartpink...@yahoo.com> wrote:
>
> Hi,
> >It is not clear whether all the variables are factor or only a few are..
> >
> >dat<- read.table(text="a coef
> coef.l coef.h
> >1 1 0.005657825001254 0.00300612956318132 0.00830952043932667
> >2 2 0.00634505314577229 0.00334102345418614 0.00934908283735844
> >3 3 0.00368668099805019 0.000289702228748421 0.00708365976735195
> >4 4 0.0056200291035751 0.00209123538827368 0.00914882281887651
> >5 5 0.00636609791030242 0.00269683889899591
> 0.0100353569216089",sep="",colClasses=rep("factor",4))
> >dat1<- dat
> >
> >
> > dat[] <- lapply(dat,function(x) as.numeric(as.character(x)))
> >
> >str(dat)
> >#'data.frame': 5 obs. of 4 variables:
> ># $ a : num 1 2 3 4 5
> ># $ coef : num 0.00566 0.00635 0.00369 0.00562 0.00637
> ># $ coef.l: num 0.00301 0.00334 0.00029 0.00209 0.0027
> ># $ coef.h: num 0.00831 0.00935 0.00708 0.00915 0.01004
> >
> >
> ># With only a subset of variables in the dataset as factors
> > dat1$a<- as.numeric(as.character(dat1$a))
> >
> >
> >dat1[sapply(dat1,is.factor)]<-
> lapply(dat1[sapply(dat1,is.factor)],function(x) as.numeric(as.character(x)))
> > str(dat1)
> >#'data.frame': 5 obs. of 4 variables:
> ># $ a : num 1 2 3 4 5
> ># $ coef : num 0.00566 0.00635 0.00369 0.00562 0.00637
> ># $ coef.l: num 0.00301 0.00334 0.00029 0.00209 0.0027
> ># $ coef.h: num 0.00831 0.00935 0.00708 0.00915 0.01004
> >
> >A.K.
> >
> >
> >
> >I have a factor data frame which I want to convert to numeric without any
> change in contents. How could I do that?
> >
> >
> > a coef coef.l coef.h
> >1 1 0.005657825001254 0.00300612956318132 0.00830952043932667
> >2 2 0.00634505314577229 0.00334102345418614 0.00934908283735844
> >3 3 0.00368668099805019 0.000289702228748421 0.00708365976735195
> >4 4 0.0056200291035751 0.00209123538827368 0.00914882281887651
> >5 5 0.00636609791030242 0.00269683889899591 0.0100353569216089
> >
> >______________________________________________
> >R-help@r-project.org mailing list
> >https://stat.ethz.ch/mailman/listinfo/r-help
> >PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> >and provide commented, minimal, self-contained, reproducible code.
> >
>
--
Charles Determan
Integrated Biosciences PhD Candidate
University of Minnesota
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