Thanks Jim for helping, Your sample data actually looks like my dataset. The one I put up looks strange for some reason so please ignore that. I have three landusenumb variables 1 2 and 3. is rep (1,2,3) correct?
When I run the following code I am getting: > mod1 <- glmer(frat ~ flandusenumb + ground.cover_lo + (1|fsite) ,family = binomial, data= mao1) > > #Calculate predicted values > newdata1 <- data.frame(ground.cover_lo = c(25,50,100), flandusenumb = rep(1,2,3)) > pred34 <- predict(mod1,newdata=newdata1,type="response") Error in UseMethod("predict") : no applicable method for 'predict' applied to an object of class "mer" Can you see what I am doing wrong? What I am aiming for is a graph which looks like this. Thanks Rebecca On Thu, Oct 10, 2013 at 5:33 PM, Jim Lemon <j...@bitwrit.com.au> wrote: > On 10/10/2013 08:35 AM, Rebecca Stirnemann wrote: > >> Dear R wizards, >> >> Though I hate to do it after weeks of my code not working I need some help >> since I cant find an example which seems to work. >> I am trying to create a graph which show the probability of predation of a >> nest on one side (either 1 to 0) or (0% to 100%) on one side >> and grass height at the bottom. I want to then add my predicted lines from >> my glmr onto the graph for three habitat types. >> >> I would like to repeat this procedure 3 times for three different grass >> heights 25- 50- 100 to see the effect size. >> >> My data: >> landusenumb landuse sitename rat ground.cover_lo 1 plantation >> far.leftroad_LHS 0 60 1 plantation far.leftroad_LHS 1 70 1 plantation >> far.leftroad_LHS 1 10 1 plantation far.leftroad_LHS 1 30 1 plantation >> far.leftroad_LHS 1 50 1 plantation far.leftroad_LHS 0 20 1 plantation >> far.leftroad_LHS 0 70 1 plantation far.leftroad_LHS 0 100 1 plantation >> far.leftroad_LHS 0 90 >> >> #Graph >> >> >> #Fit model >> >> mod1<- glmer(frat ~ flandusenumb + ground.cover_lo + (1|fsite) ,family = >> binomial, data= mao1) >> >> >> #Calculate predicted values >> >> newdata1<- data.frame(ground.cover_lo = seq(0,10,length=100), flandusenumb >> = rep(1,2,3)) >> >> pred34<- predict(mod1,newdata=newdata1,**type="response") >> >> >> >> #Plot model predicted curves >> >> plot(c(0,100),c(0,1),type="n",**xlab="grasscover",ylab="**Probability of >> predation") >> >> lines(newdata1$frat,pred34,**lwd=3,col="blue") >> >> >> Hi Rebecca, > First, your sample data are a bit mangled, and should look like this: > > mao1 > > landusenumb landuse sitename rat ground.cover_lo > 1 plantation far.leftroad_LHS 0 60 > 1 plantation far.leftroad_LHS 1 70 > 1 plantation far.leftroad_LHS 1 10 > 1 plantation far.leftroad_LHS 1 30 > 1 plantation far.leftroad_LHS 1 50 > 1 plantation far.leftroad_LHS 0 20 > 1 plantation far.leftroad_LHS 0 70 > 1 plantation far.leftroad_LHS 0 100 > 1 plantation far.leftroad_LHS 0 90 > > If you want the predicted values with ground cover as above, then: > > ground.cover_lo = c(25,50,100) > > The variable names in the first model don't match those in the data frame, > but I assume these were typos. What does "pred34" look like? This will tell > you what function you should be using to plot it. > > Jim > -- www.samoanbirds.com [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.