Hi, May be this help: Please dput() the example dataset: Caso<- structure(list(`9` = structure(c(2, 10), .Names = c("0", "1")), `13` = structure(c(2, 4), .Names = c("0", "2"))), .Names = c("9", "13"))
nm<-unique(unlist(lapply(Caso,names))) vec1<- numeric(length(nm)) names(vec1)<- nm do.call(rbind,lapply(Caso,function(x){ indx<- names(vec1)%in% names(x); vec1[indx]<-x;vec1 })) # 0 1 2 #9 2 10 0 #13 2 0 4 A.K. ----- Original Message ----- From: Sebastian Kruk <residuo.so...@gmail.com> To: R-help <r-help@r-project.org> Cc: Sent: Thursday, September 26, 2013 2:02 PM Subject: [R] Help with list I have a list that gives me the number of occurrences of numbers 1, 2, 3 and 4. Sometimes a single in a casa just appears 0 and 1, in others only 2, and every combination you can think of. Eg > Caso [1:2] $ `9` 0 1 2 10 $ `13` 0 2 2 4 Can I turn it into a matrix consisting of 4 columns in which I put the number of occurrences of the previous numbers, and for cases where it does not appear any of those values put 0? Regards, Sebastian. [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.