Hi,
testing<- read.table(text="0:00,0.88
0:05,
0:20,0.6
0:25,0.14
0:30,0.25
0:35,0.5
0:40,0.25
0:45,0.13",sep=",",header=FALSE,stringsAsFactors=TRUE)
# After reading the file using ?read.csv(), try:
plot(as.numeric(testing$V1),testing$V2,xaxt="n",xlab="TimeStamp",ylab="IntSollrr")
axis(1,as.numeric(testing$V1),levels(testing$V1))
A.K.
Hi guys,
I am trying to plot the attached .csv (located in my C:\R
folder). The .csv has 2 columns, where the first 6 rows are headers and
look something like this:
CSV-Export,
,
,SENS0700
,28728
TimeStamp,IntSolIrr
hh:mm,W/m^2
0:00,0.88
0:05,
0:20,0.6
0:25,0.14
0:30,0.25
0:35,0.5
0:40,0.25
0:45,0.13
If I were to type this
> setwd("C:/R")
> testing=read.csv("testing.csv", skip=6, header = FALSE)
> plot(testing$V2)
I get a nice graph
But when I try to plot the graph against time instead and type this
> setwd("C:/R")
> testing=read.csv("testing.csv", skip=6, header = FALSE)
> plot(testing$V1,testing$V2)
The time gets all screwed up and are no longer in order.
Is there a way to solve this? I also tried reading the
documentation on zoo, but I cannot find how to tell R to treat only the
first column as time in hh:mm format (I get a warning instead using
read.zoo)
Thank you!
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