Catalin,
first, keep the communication on the list, so it gets documented also for
others.
Second, my code does work for an example I made up myself, but if you
don't "provide commented, minimal, self-contained, reproducible code" (as
the posting guide asks you to; see last line of this e-mail), it is
unlikely that someone could be of further help.
Regards -- Gerrit
On Mon, 26 Aug 2013, catalin roibu wrote:
Hello!
Your code give me the same month values for each year from interval. I want
12 month for each year!.
Eg
year month value
1901 1 3.5
1901 2 2.5
On 26 August 2013 14:35, Gerrit Eichner
<gerrit.eich...@math.uni-giessen.de>wrote:
Hello, Catalin,
assume your data frame is as simple as
A <- data.frame( year = <years>, month01 = <values01>, ....,
+ month12 = <values12>)
then, e.g.,
reshape( A, varying = c( "month01", ...., "month12"),
+ v.names = "Values", timevar = "Month", direction = "long")
should do what you want. For details see ?reshape
Hth -- Gerrit
On Mon, 26 Aug 2013, catalin roibu wrote:
Dear all!
I have a data frame composed by 13 columns (year, and 12 months). I want
to
transform this data base in another like this
year month values
1901 1
1901 2
1901 3
.....
1901 12
1902 1
1902 2
....
1902 12
Is there a possibility to succeed that in R?
Thank you!
best regards!
CR
--
---
Catalin-Constantin ROIBU
Lecturer PhD, Forestry engineer
Forestry Faculty of Suceava
Str. Universitatii no. 13, Suceava, 720229, Romania
office phone +4 0230 52 29 78, ext. 531
mobile phone +4 0745 53 18 01
+4 0766 71 76 58
FAX: +4 0230 52 16 64
silvic.usv.ro
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--
---
Catalin-Constantin ROIBU
Lecturer PhD, Forestry engineer
Forestry Faculty of Suceava
Str. Universitatii no. 13, Suceava, 720229, Romania
office phone +4 0230 52 29 78, ext. 531
mobile phone +4 0745 53 18 01
+4 0766 71 76 58
FAX: +4 0230 52 16 64
silvic.usv.ro
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