Thanks Matthias,
I tried that, but received the following error message:
Error in image.default(1:nc, 1:nr, x, xlim = 0.5 + c(0, nc), ylim = 0.5 + :
dimensions of z are not length(x)(+1) times length(y)(+1)
-Peter
At 10:18 AM +0200 5/15/08, Matthias Kohl wrote:
Dear Peter,
heatmap.2(z, dendrogram = "none", Rowv = FALSE, Colv = FALSE)
should do what you want.
Best,
Matthias
Peter Scacheri wrote:
Using the heatmap.2 function, I am trying to generate a heatmap of
a 2 column x 500 row matrix of numeric values. I would like the
1st column of the matrix sorted from the highest to the lowest
values - so that the colors reflected in the first column of the
heatmap (top to bottom) go from red to green.
After sorting the matrix (z), I tried the following command, but
the data remains clustered.
heatmap.2((z),col=greenred(100),dendrogram=NULL,Rowv=FALSE)
I also tried the following, but the data remained clustered.
heatmap.2((z),col=greenred(100),Colv=1:ncol(z))
ANY IDEAS??
Thanks so much,
Peter
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Dr. Matthias Kohl
www.stamats.de
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and provide commented, minimal, self-contained, reproducible code.
