Hello,

There's a bug in the line

for (i in 1:length(dim(somdata.xyf$codes$X)[2]))

length() is always 1, you can use simply 1:dim(...)[2] or even simpler

for(i in 1:ncol(somdata.xyf$codes$X))

As for a way without a loop, you could use ?sapply:

sapply(1:ncol(somdata.xyf$codes$X), function(i) plot(...))

But I believe the loop is far more readable, and preferable.

Rui Barradas

Em 31-07-2013 00:25, Ben Harrison escreveu:
On 30 July 2013 21:35, Rui Barradas <ruipbarra...@sapo.pt> wrote:
Hello,

Maybe the following does it.

op <- par(mfrow=c(2, 3))

for(i in 1:6){
         plot(somdata.xyf,
              type="property",
              property=somdata.xyf$codes$X[, i],
              main=colnames(somdata.xyf$codes$X)[i])
}

par(op)


Hope this helps,

Rui Barradas

Thanks Rui,
that does it for sure. I had come to that solution, but just realised
by looking at it again, I could change
for (i in 1:6)
with
for (i in 1:length(dim(somdata.xyf$codes$X)[2]))

I was also wondering if there was a way to do it without a for loop,
but in this case it's a very small number of iterations, so probably
not worth it.

Ben


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