Hi,
?max
?min
max(mydates)
#[1] "2007-06-22"
min(mydates)
#[1] "2004-02-13"
max(mydates)-min(mydates)
Time difference of 1225 days
max(as.numeric(mydates))-min(as.numeric(mydates))
#[1] 1225
A.K.
----- Original Message -----
From: Peter Maclean <pmaclean2...@yahoo.com>
To: "r-help@r-project.org" <r-help@r-project.org>
Cc:
Sent: Sunday, July 28, 2013 3:20 PM
Subject: Re: [R] Extracting Current and Old Date
#This my look trivial but has been killing my time
#I want to extract most current and old date from mydates #variable that has
more than 10,000 observation.
#Get days
# use as.Date( ) to convert strings to dates
mydates <- as.Date(c("2007-06-22", "2007-05-21", "2004-04-13",
"2004-03-11","2004-02-13",))
#Is there a way/fuction to extract mostcurrent date
#from mydates variable
mostcurrent <- as.Date(c("2007-06-22"))
#Is there a way/function to extract olddate
#from mydates variable
olddate <- as.Date(c("2004-02-13"))
#Days between most current and old dayte
days <- as.numeric(mostcurrent - olddate)
Peter Maclean
Department of Economics
UDSM
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and provide commented, minimal, self-contained, reproducible code.
