You got exactly what you were asking for: the value the last time through
the loop. If you are trying to capture all 11 values, then you might
consider a list:
d<-as.vector(levels(a2$combin2))
a1 <- b1 <- vector('list',11)
for (i in 1:11){
a1[[i]] <-a2[a2$combin2%in%d[i],]
b1[[i]]<-b0[b0$Date%in%(a1[[i]]$Date),]
}
or using 'lapply'
result <- lapply(1:11, function(.index){
a1 <- a2[a2$combin2 %in% d[.index],]
list(a1=a1, b1=b0[b0$Date %in% a1$Date, ]
})
'result' is a list with both values in it for each iteration.
On Wed, May 14, 2008 at 11:13 AM, J S <[EMAIL PROTECTED]> wrote:
>
> Dear R community,
>
> I wrote a small program using for loop but it does not make cycles.
>
> My data: Dataframes: a2, a1, b0 and b1. Vector: d
>
> I would like to get b1 for each of i., i.e. totally 11. However, the
> program gives me b1 only for the last i =11.
>
> d<-as.vector(levels(a2$combin2))
> for (i in 1:11){
> a1<-a2[a2$combin2%in%d[i],]
> b1<-b0[b0$Date%in%(a1$Date),]
> }
>
> Your help is appreciated. Maybe someone could also recommend me good
> literature on for loops in R?
>
> Thanks,
> Julia
> _________________________________________________________________
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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?
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