Hello,
If you create the 3rd column like that, it will be named V3, not z. You
must do one of
myDataframe$z <- I(myList)
myDataframe[["z"]] <- I(myList)
Rui Barradas
Em 19-07-2013 22:28, David Winsemius escreveu:
On Jul 19, 2013, at 12:54 PM, Pete Brecknock wrote:
Hi
I am trying to add the contents of the list "myList" to a new column "z" in
the data frame "myDataframe"
myList <- list(c("A1","B1"), c("A2","B2","C2"), c("A3","B3"))
myDataframe <- data.frame(x=c(1,2,3), y=c("R","S","T"))
Would like to produce
x y z
1 R A1,B1
2 S A2,B2,C2
3 T A3,B3
where z is a character string holding the contents of the different elements
of the list.
myDataframe[[3]] <- I(myList)
myDataframe
x y z
1 1 R A1, B1
2 2 S A2, B2, C2
3 3 T A3, B3
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