Hello,
The functions in stackoverflow need a date 'format' argument.
# Functions from
#
http://stackoverflow.com/questions/1995933/number-of-months-between-two-dates
# with a 'format' argument added
#
# turn a date into a 'monthnumber' relative to an origin
monnb <- function(d, format = "%Y-%m-%d") {
lt <- as.POSIXlt(as.Date(d, origin="1900-01-01", format = format))
lt$year*12 + lt$mon
}
# compute a month difference as a difference between two monnb's
mondf <- function(d1, d2, format = "%Y-%m-%d") {
monnb(d2, format = format) - monnb(d1, format = format)
}
dat1 <- read.table(text = "
ID date
1 4/12/2008
1 4/13/2008
1 5/11/2008
2 3/21/2009
2 4/22/2009
2 8/05/2009
", header = TRUE)
dat2 <- data.frame(ID = dat1$ID, month = mondf("01/01/2008", dat1$date,
format = "%m/%d/%Y") + 1)
# Now keep just the last one if month diffs are equal
result <- with(dat2, aggregate(month, list(ID, month), FUN = tail, 1))[1:2]
names(result) <- names(dat2)
result
Hope this helps,
Rui Barradas
Em 11-07-2013 11:03, andrija djurovic escreveu:
Hi.
See
http://stackoverflow.com/questions/1995933/number-of-months-between-two-dates
Andrija
On Thu, Jul 11, 2013 at 11:56 AM, Gallon Li <gallon...@gmail.com> wrote:
My data are from 2008 to 2010, with repeated measures for same subjects. I
wish to compute number of months since january 2008.
The data are like the following:
ID date
1 4/12/2008
1 4/13/2008
1 5/11/2008
2 3/21/2009
2 4/22/2009
2 8/05/2009
...
the date column are in the format "%m/%d/%y". i wish to obtain
ID month
1 4
1 4
1 5
2 15
2 16
2 20
...
also, for the same ID with two identical month, I only want to keep the
last one. can any expert help with this question?
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
