Thanks to Gabor Grothendieck & Ted Harding. both solutions work very nicely.
--- Gabor Grothendieck <[EMAIL PROTECTED]> wrote: > Try this (no gsub required): > > as.chron(as.Date(xx, "%b %d, %Y")) > > On Sat, May 10, 2008 at 12:49 PM, John Kane > <[EMAIL PROTECTED]> wrote: > > I am cleaning up some character data to convert to > > dates using chron. The regex that I am using work > fine > > but there should be a better way to do this. Can > > anyone suggest a cleaner bit of code than the > gsub, > > sub approach? Thanks > > > > #Test Run on dates. > > xx <- c("May 1, 2007", > > "May 2, 2007", > > "May 3, 2007", > > "May 4, 2007", > > "May 5, 2007", > > "May 6, 2007", > > "May 7, 2007", > > "May 8, 2007", > > "May 9, 2007", > > "May 10, 2007", > > "May 11, 2007", > > "May 12, 2007") > > yy <- gsub(" +", "/", xx) ; yy > > zz <- sub(",", "", yy) ; zz > > library(chron) > > ttdates <- chron(zz, format = c(dates = > "mon/d/y")) > > > > ______________________________________________ > > R-help@r-project.org mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, > reproducible code. > > > __________________________________________________________________ [[elided Yahoo spam]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.