On 28/06/2013 10:46 AM, Kaptue Tchuente, Armel wrote:
Please could you explain what you mean by several typos in my code?

1. img is passed as an argument, but never used.
2. There is no closing brace on the function body.
3.  You set the dimension to n*m, when I believe you wanted c(n, m).

Duncan Murdoch


Anyway, it works very well and keep in minds that here I just wrote a very 
simple code to illustrate what I really want since in the reality, the program 
is more complex than what you see.
May be I'm wrong but I also prefer to call this fortran function because I 
realized that (i) R is not very efficient for large data sets reading and 
processing and (ii) the speed of execution in Fortran is faster than in C.

Armel

-----Original Message-----
From: Duncan Murdoch [mailto:murdoch.dun...@gmail.com]
Sent: Friday, June 28, 2013 9:30 AM
To: Kaptue Tchuente, Armel
Cc: r-help@r-project.org
Subject: Re: [R] How to create a function returning an array ?

On 28/06/2013 10:18 AM, Kaptue Tchuente, Armel wrote:
> @ Duncan, I have already used the syntax that you proposed before
> asking for help by writing something like
> > read_ts<-function(n,m,img) {
> >  out<-.Fortran("read_ts",
> >                as.integer(n),
> >                as.integer(m),
> >                img=as.single(rnorm(n*m)))
> > return(out$img)
> > alpha<-read_ts(n,m)
> > dim(alpha)<-c(n*m)
> > alpha<-t(alpha)
> My worry with this syntax is that (i) the program is not very efficient because n 
and m are very big and these two additional instructions (dim(alpha)<-c(n*m and 
alpha<-t(alpha) can be skipped just by directly declaring img as an array in fortran 
instead of a vector and (ii) the syntax will become more complex dealing with a 
multidimensional array instead of a matrix as in this example.
> And this is why I'm looking for the correct instruction to declare img as an 
array instead of a vector.

There are several typos in your code above, but I think your intention is clear.

You can do what you are asking for, but not with .Fortran.  It only handles 
vectors for input and output.  You'll need to use .Call (which means writing in 
C or C++).  If you're familiar with C++, using Rcpp is probably the easiest way 
to do this.  If not, I'd rewrite the Fortran code to avoid the need for the 
transpose at the end, and do

dim(out$img) <- c(n,m)
return(out$img)

within your read_ts function.  I think this is reasonably efficient.

Duncan Murdoch


>
> Armel
>
> -----Original Message-----
> From: Duncan Murdoch [mailto:murdoch.dun...@gmail.com]
> Sent: Friday, June 28, 2013 8:16 AM
> To: David Winsemius
> Cc: Kaptue Tchuente, Armel; r-help@r-project.org
> Subject: Re: [R] How to create a function returning an array ?
>
> On 27/06/2013 11:38 PM, David Winsemius wrote:
> > On Jun 27, 2013, at 8:04 PM, Kaptue Tchuente, Armel wrote:
> >
> > > Hi there,
> > >
> > > I would like to know how to change the line
> > > "img=as.single(rnorm(m)))" such that instead of being a vector of
> > > length m as it is now, img is an array of dimension c=(n,m,o) for
> > > instance
> > >
> > > ---------------------------------
> > > read_ts<-function(n,m,o,img) {
> > >   out<-.Fortran("read_ts",
> > >                as.integer(n),
> > >                as.integer(m),
> > >                as.integer(o),
> > >                img=as.single(rnorm(n)))
> > >   return(out$img)
> > > ------------------------------------------
> > >
> >
> > Well, assuming that  the 'out$img' object has a R-length of n*m*o , 
wouldn't if be simpler to just change the return call to:
>
> In fact, out$img has a length of n, same as on input.  .Fortran won't change 
the length of its arguments.
>
> Duncan Murdoch
>
> >
> > return( array( out$img, dim=c(n,m,o) )
> >
> > I don't think you wnat start naming your dimension vectors "c".
> >
>


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