this can be more efficiently coded using indexing, e.g.,
x <- c(1,2,3,2,1,2,3)
n <- length(x)
x[2:n] / x[1:(n-1)]
Best,
Dimitris
----
Dimitris Rizopoulos
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
Quoting Jorge Ivan Velez <[EMAIL PROTECTED]>:
Hi Lydia,
Try this:
# Function
ratio=function(x){
temp=NULL
for (n in 1:length(x)) temp=c(temp,x[n]/x[n-1])
temp
}
# Example
x=c(1,2,3,2,1,2,3)
ratio(x)
[1] 2.0000000 1.5000000 0.6666667 0.5000000 2.0000000 1.5000000
HTH,
Jorge
On Mon, May 12, 2008 at 9:52 AM, Lydia N. Slobodian <[EMAIL PROTECTED]> wrote:
Hello. I'm trying find the ratios between each of the integers in a
vector. I have:
for (n in x) {
ratio <- (x[n]/x[n-1])
ratio.all <- c(ratio.all, ratio)
}
Of course this doesn't work, nor does diff(n)/diff(n-1). Is there a
way to specify a pair of integers in a vector?
Thank you,
Lydia
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