Hello,
I'm not completely sure I've understood. Your variable 'letters' iholds
the names of the data.frames? If so it's better if you put yoyr
data.frames in a list and then use that list. Something like
lst <- list(A, B)
for (i in seq_along(lst)){
lst[[i]][["Rate"]] <- ROC(lst[[i]][["population"]])
}
Hope this helps,
Rui Barradas
Em 14-04-2013 18:19, Sparks, John James escreveu:
Dear R Helpers,
I have a large number of data frames and I need to create a new column
inside each data frame. Because there is a large number, I need to "loop"
through this, but I don't know the syntax of assigning a new column name
dynamically.
Below is a simple example of what I need to do. Assume that I have to do
this for all 26 letters and you should see the form of the problem.
Any help would be much appreciated. If more information is needed, please
let me know.
Many thanks.
--John Sparks
library(quantmod)
A <- data.frame(population=c(100, 300, 5000, 2000, 900, 2500))
A$Rate<-ROC(A["population"])
B <- data.frame(population=c(200, 300, 4000, 3000, 2000, 500))
B$Rate<-ROC(B["population"])
letters<-c("A","B")
length(letters)
#for (i in letters){
# HELP!
#}
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
