That is very helpful Rui, thanks so much!
On Wed, Apr 10, 2013 at 1:54 PM, Rui Barradas <ruipbarra...@sapo.pt> wrote: > Hello, > > You should provide us with a data example, like the posting guide asks you > to. > Without one, you could adapt the following example to your case > > > # Make up some data > dat <- data.frame(X = rnorm(200), Y = rnorm(200)) > > # Divide into subsets of 60 rows each and compute the col means > grp <- rep(1:(1 + nrow(dat) / 60), each = 60)[seq_len(nrow(dat))] > do.call(rbind, lapply(split(dat, grp), colMeans)) > > > Hope this helps, > > Rui Barradas > > Em 10-04-2013 18:46, Ye Lin escreveu: > >> Hey All, >> >> I have a large dataset and I want to calculate the average of each column >> then return a new dataset. >> >> Here is my question: I dont know if there is a function that can allow me >> to calculate the average every 60 records of data in the whole dataset, >> and >> return a new data frame. Not sure if I have to divide the dataset first >> for >> every 60, then do the mean or can i directly do that. >> >> thanks for your help! >> >> >> cici >> >> [[alternative HTML version deleted]] >> >> ______________________________**________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/**listinfo/r-help<https://stat.ethz.ch/mailman/listinfo/r-help> >> PLEASE do read the posting guide http://www.R-project.org/** >> posting-guide.html <http://www.R-project.org/posting-guide.html> >> and provide commented, minimal, self-contained, reproducible code. >> >> [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
