Use lag.xts: R> lag(x,-1) aaa bbb ccc ddd 2001-01-02 181.1751 243.24 1689.10 267.15 2001-01-03 181.6126 242.09 1737.86 267.10 2001-01-04 NA NA NA NA
Note that the sign of k is different for lag.xts than lag.zoo (and lag.default). R> lag(as.zoo(x),-1) aaa bbb ccc ddd 2001-01-03 179.7061 239.11 1712.6 271.10 2001-01-04 181.1751 243.24 1689.1 267.15 Best, -- Joshua Ulrich | about.me/joshuaulrich FOSS Trading | www.fosstrading.com R/Finance 2013: Applied Finance with R | www.RinFinance.com On Sun, Apr 7, 2013 at 8:34 AM, Michela <freeri...@gmail.com> wrote: > i have an xts object: > > aaa bbb ccc ddd > 2001-01-02 179.7061 239.11 1712.60 271.10 > 2001-01-03 181.1751 243.24 1689.10 267.15 > 2001-01-04 181.6126 242.09 1737.86 267.10 > > i simply want translate upward all the values > So values in first row are lost. All others traslate upward > > In my example, xts object should become: > > aaa bbb ccc ddd > 2001-01-02 181.1751 243.24 1689.10 267.15 > 2001-01-03 181.6126 242.09 1737.86 267.10 > 2001-01-04 NA NA NA NA > > Any idea how to do this upward translation? > > thanks > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.