Hi,
You could also try:
library(plyr)
df1<- df
df2<- df
df$y<-revalue(df$y,c("e"="others","f"="others","g"="others"))
df$y
#[1] a b c d others others others
#or
df1$y<-mapvalues(df1$y,from=c("e","f","g"),to=rep("others",3))
levels(df1$y)
#[1] "a" "b" "c" "d" "others"
#or
levels(df2$y)[match(c("e","f","g"),levels(df2$y))]<-"others"
levels(df2$y)
#[1] "a" "b" "c" "d" "others"
A.K.
________________________________
From: Lorenzo Isella <lorenzo.ise...@gmail.com>
To: "r-h...@stat.math.ethz.ch" <r-h...@stat.math.ethz.ch>
Sent: Monday, March 25, 2013 6:18 PM
Subject: [R] Reassign Multiple Factors to same Factor Value
Dear All,
Probably something very easy, but I am looking for the most efficient ways to
achieve this.
Consider the following snippet
y<-c('a','b','c','d','e','f','g')
x<-rnorm(length(y))
df<-data.frame(y,x)
leading to
> df$y
[1] a b c d e f g
Levels: a b c d e f g
Now, I would like to replace levels ('e','f','g') of df$y with a new level
'other' so that levels(df$y) returns
a b c d other
What is the easiest way to achieve this, considering that
df$y[5:7]<-'other'
Does not work?
Cheers
Lorenzo
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and provide commented, minimal, self-contained, reproducible code.
