> -----Original Message-----
> From: [email protected] [mailto:r-help-bounces@r-
> project.org] On Behalf Of Szumiloski, John
> Sent: Tuesday, March 12, 2013 10:39 AM
> To: Hadley Wickham
> Cc: [email protected]
> Subject: Re: [R] ls() with different defaults: Solution;
>
>
>
> -----Original Message-----
> From: Hadley Wickham [mailto:[email protected]]
> Sent: Tuesday, 12 March, 2013 1:34 PM
> To: Szumiloski, John
> Cc: [email protected]
> Subject: Re: [R] ls() with different defaults: Solution;
>
> On Tue, Mar 12, 2013 at 12:59 PM, Szumiloski, John
> <[email protected]> wrote:
> > Dear useRs,
> >
> > Some time ago I queried the list as to an efficient way of building a
> function which acts as ls() but with a different default for all.names:
> >
> > http://tolstoy.newcastle.edu.au/R/e6/help/09/03/7588.html
> >
> > I have struck upon a solution which so far has performed admirably.
> In particular, it uses ls() and not its explicit source code, so only
> has a dependency on its name and the name of its all.names argument.
> Here is my solution:
> >
> > lsall <- function(...) {
> >
> > thecall <- as.call(c(as.name('ls'), list(...)))
> > newcall <- match.call(definition=ls, call=thecall)
> > if( !('all.names' %in% names(newcall)) ) newcall[['all.names']]
> <- TRUE
> > eval(newcall, envir=parent.frame())
> >
> > }#### end lsall
>
> Why not just do:
>
> lsall <- function(..., all.names = TRUE) {
> ls(..., all.names = all.names)
> }
>
> ? Then the function practically documents itself.
>
> The search path of the internal ls() is not the same as that of the
> called lsall(). You then get (e.g.)
>
> > lsall2()
> [1] "..." "all.names"
>
> John
>
>
Then how about
lsall <- function(..., all.names = TRUE) {
ls(..., all.names = all.names, envir=parent.frame())
}
Hope this is helpful,
Dan
Daniel J. Nordlund
Washington State Department of Social and Health Services
Planning, Performance, and Accountability
Research and Data Analysis Division
Olympia, WA 98504-5204
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