What about read.table()?
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000 Dijon, FRANCE
+33(0)3.80.39.63.06
ivan.calan...@u-bourgogne.fr
http://biogeosciences.u-bourgogne.fr/calandra
Le 12/03/13 10:03, Roslina Zakaria a écrit :
Dear r-users,
Originally my data is in notepad. I use data.frame(...) to convert the data into columns but it has no header. The data below is what I got in R. I would like to extract these data:
19710629 39.3 19701126
19720629 33.8 19720517
...
when I use data2_30min[1, cbind(1,3,5)] command the result is NULL.
Then I tried data2_30min[1], it gives me the whole set of data. I suspect the data is stored in a cell.
My question is, how do I split the data from dataframe into some columns which separating the data by spaces. Many examples given on how to split the data with the header.
The codes and data are given below. Thank you so much for your help.
head(data_30min,10); tail(data_30min,10)
data2_30min <- data.frame(data_30min)
head(data2_30min,10); tail(data2_30min,10)
head(data_30min,10); tail(data_30min,10)
data2_30min[1]
data_30min
1 19710629 080000(PARTIAL) 39.3 at interval beginning 19701126 010326
2 19720629 080000(PARTIAL) 33.8 at interval beginning 19720517 144507
3 19730629 080000(PARTIAL) 32.2 at interval beginning 19720910 135747
4 19740629 080000(PARTIAL) 38.9 at interval beginning 19731003 124849
5 19750629 080000 43.3 at interval beginning 19750105 173500
6 19760629 080000(PARTIAL) 101.5 at interval beginning 19750809 111800
7 19770629 080000(PARTIAL) 39.4 at interval beginning 19760917 141200
8 19780629 080000 38.5 at interval beginning 19780508 195400
9 19790629 080000(PARTIAL) 39.0 at interval beginning 19790602 142222
10 19800629 080000(PARTIAL) 94.6 at interval beginning 19800329 063532
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