you can do below but there's no way of getting arounf having NAs in your
final matrix.
d1<-as.matrix(rnorm(5))
d2<-as.matrix(rnorm(3))
d3<-as.matrix(rnorm(6))
templist <- list(d1,d2,d3)
maxnum <- max(sapply(templist,length))
print(maxnum)
temp <- lapply(templist,function(.mat) {
if (nrow(.mat) < maxnum) {
return(c(.mat,rep(NA,maxnum-nrow(.mat))))
} else {
return(.mat)
}
})
finalmat <- as.matrix(do.call(cbind,temp))
print(finalmat)
On Mon, May 5, 2008 at 6:46 PM, T.D.Rudolph wrote:
I have numerous objects, each containing continuous data representing
the
same variable, movement rate, yet each having a different number of
rows. e.g.
d1<-as.matrix(rnorm(5))
d2<-as.matrix(rnorm(3))
d3<-as.matrix(rnorm(6))
How can I merge these three columns side-by-side in order to create a
table
regardless of the difference in length? I wish to analyze the output
in a
spreadsheet format.
Thanks!
Tyler
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