Hi,
For the first case:
lst2<-lapply(x.list, calcnorm2, x.list)
lapply(lst2,function(x) do.call("c",x))
#[[1]]
#[1] 0.00000 31.75257
#[[2]]
#[1] 31.75257 0.00000
A.K.
For the second case:
lst1<-as.list(data.frame(t(apply(x,1,calcnorm2.const,x))))
names(lst1)<- NULL
lst1
#[[1]]
#[1] 0.00000 31.75257
#[[2]]
#[1] 31.75257 0.00000
A.K.
----- Original Message -----
From: ishi soichi <soichi...@gmail.com>
To: r-help <r-help@r-project.org>
Cc:
Sent: Sunday, March 10, 2013 1:18 AM
Subject: Re: [R] list + lapply insead of matrix + apply
there is a typo.
lapply(x.list, calcnorm, x.list)
should be
lapply(x.list, calcnorm2, x.list)
sorry.
2013/3/10 ishi soichi <soichi...@gmail.com>
> I need to develop a simple list manipulation. Although it seems easier to
> do it in matrix form, but I need it in list form.
>
> I have a matrix
>
> x <- matrix(c(12.1, 3.44, 0.1, 3, 12, 33.1, 1.1, 23), nrow=2)
>
> for list form example, the conversion is
>
> x.list <- lapply(seq_len(nrow(x)), function(i) x[i,])
>
>
> ### list version
> calcnorm=function(a, b){
> diff <- mapply("-", a, b)
> diff2 <- mapply("*", diff, diff)
> sqrt.diff <-sqrt(sum(diff2))
> return(sqrt.diff)
> }
> calcnorm2=function(a,X){
> lapply(X, calcnorm, a)
> }
> lapply(x.list, calcnorm, x.list)
>
> [[1]]
> [[1]][[1]]
> [1] 0
>
> [[1]][[2]]
> [1] 31.75257
>
>
> [[2]]
> [[2]][[1]]
> [1] 31.75257
>
> [[2]][[2]]
> [1] 0
>
>
> ### matrix version
> calcnorm.const=function(a,b){
> return(sqrt((a-b)%*%(a-b)))
> }
> calcnorm2.const=function(a,data){
> apply(data,1,calcnorm.const,a)
> }
> apply(x,1,calcnorm2.const,x)
>
> [,1] [,2]
> [1,] 0.00000 31.75257
> [2,] 31.75257 0.00000
>
> Ideally, for later purposes, the list form of the output should be
> something like
>
> [[1]]
> [1,] 0 31.75257
> [[2]]
> [2,] 31.75257 0
>
> I am getting confused here. Could anyone help me out for the right output
> FORM?
>
> ishida
>
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