Hello,
Try
x <- scan(text = " 1 1 3 2 3 1 1
2 3 3 2")
sapply(unique(x), function(.x) which(x == .x))
Hope this helps,
Rui Barradas
Em 06-03-2013 11:26, eliza botto escreveu:
Dear useRs,
I have a matrix in the following form
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11]
1 1 3 2 3 1 1 2 3 3 2
and following is my desired output (combining the column headers, having same
values).
a<-1,2,6,7
b<-3,5,9,10
c<-4,8,11
Thanks in advance
Elisa
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