On 13-03-03 3:39 PM, Oleguer Plana Ripoll wrote:
Dear Milan and other users,
Thank you for your help, it worked. The problem is that the function "do.call"
is not ready for vectors and I need it in order to integrate it afterwards.
do.call() is fine, it's the argument list that needs fixing. Construct
a list containing elements q, shape, and scale.
With the pweibull, I can write:
pweibull(1,shape=1)
pweibull(2,shape=1)
pweibull(1:2,shape=1)
When I do the same with the do.call, I obtain an error:
do.call("pweibull",c(q=1,list(shape=1,scale=1)))
do.call("pweibull",c(q=2,list(shape=1,scale=1)))
do.call("pweibull",c(q=1:2,list(shape=1,scale=1)))
Error in pweibull(q1 = 1L, q2 = 2L, shape = 1, scale = 1) :
unused argument(s) (q1 = 1, q2 = 2)
Do you know how can I solve it?
parameters <- list(shape=1, scale=1)
do.call("pweibull", c(list(q=1:2), parameters))
Duncan Murdoch
Thank you,
Oleguer
On 03/03/2013, at 20:32, Milan Bouchet-Valat <nalimi...@club.fr> wrote:
Le dimanche 03 mars 2013 à 19:49 +0100, Oleguer Plana Ripoll a écrit :
Hello everyone,
I have a quick question but I am stuck with it and I do not know how
to solve it.
Imagine I need the distribution function of a Weibull(1,1) at t=3,
then I will write pweibull(3,1,1).
I want to keep the shape and scale parameters in a list (or a vector
or whatever). Then I have
parameters<-list(shape=1,scale=1)
but when I write pweibull(3,parameters) I get the following error:
Error in pweibull(q, shape, scale, lower.tail, log.p) :
Non-numeric argument to mathematical function
I have to write pweibull(3,parameters[[1]],parameters[[2]]) but I am
very interested in being able to write pweibull(3,parameters).
Does anyone know how to solve it?
What you are looking for is do.call():
parameters <- list(q=3, shape=1, scale=1)
do.call("pweibull", parameters)
or
parameters <- list(shape=1, scale=1)
do.call("pweibull", c(q=3, parameters))
Regards
Thank you very much,
Oleguer Plana
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